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Molodets [167]
1 year ago
10

A figure is located at (2, 0), (2, -3), and (5, 0) on a coordinate plane. What kind of 3-D shape would be created if the figure

was rotated around the x-axis? Include the dimensions of the 3-D shape.
Answer: 3-D Shape: _____ Height: _____ Diameter: _____

Mathematics
1 answer:
expeople1 [14]1 year ago
5 0

When the shape is rotated around the x-axis, a 3-D shape would be formed

The 3-D shape is a tetrahedron with radius 2 and height 4

<h3>How to determine the 3-D shape?</h3>

The coordinates of the figure are given as:

(2, 0), (2, −3), and (5, 0)

The above coordinates represent a triangle that has one of its sides on the x-axis.

So, when the shape is rotated across the axis, the other two lines would make a diagonal the side on the x-axis.

This movement would form a tetrahedron with the following dimensions

  • Height = Distance (2, 0) and (5, 0) i.e. 3 units
  • Radius = Distance (2, 0) and (2, −3) i.e. 3 units

Hence, the 3-D shape is a tetrahedron with radius 3 and height 3

Read more about three dimensional shapes at:

brainly.com/question/12280037

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Find the measures of the interior angles of the triangle.
jeka94

Answer:

∠A = 30°

∠B = 60°

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Step-by-step explanation:

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Knowing that, you now know <em>∠C is 90°</em>

Now, to find ∠B, you should use the following equation:

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This means that the sum of the three angles of a triangle gives 180. ALWAYS. So to find the missing angle, ∠B, do the following:

Fill the values of the equation with the angles you now know:

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<em>B = 60</em>

<em>Hope it helps!!</em>

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