Vertex=(-1,0)
x^2-2x-1
y=− ( x + 1 )^2 + 0
Use the vertex form, y=a(x−h)^2+k, to determine the values of a, h, and k.
Find the vertex (h,k) = (-1,0)
Answer:
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Step-by-step explanation:
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Answer:
mm the answer would be
Step-by-step explanation:
1 may be
Answer:
B. -5
Step-by-step explanation:
this is quite simple, so what you are going to want to do is multiply -3 by 4, and -16, so distribute that and you'll end up with
-12x+48= -12
then you want to subtract 48 from both side to leave the x on one side alone
that will be -12x= -60
after that you have to divide both sides by -12 to find your x
so then you will see that your x is = -5! hope this helps!!