Answer:
bure
Explanation:
hiß haoi óie den la Opie ñsji cßns
The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
Learn more about Tension calculations : brainly.com/question/24994188
The acceleration of a different speck of dust is 40 m/s.
Since the radius is been given as double and angular velocity will be constant, we can calculate the centripetal acceleration as
a = (2r)ω²
If we substitute the given values of r= 2r , and ω²= 20m/s.
Then we have

Therefore, acceleration of a different speck of dust is 40 m/s.
<h3>What is centripetal acceleration?</h3>
centripetal acceleration can be regarded as acceleration of a body that is traversing a circular path.
CHECK THE COMPLETE QUESTIONS;
A speck of dust on a spinning dvd has a centripetal accelera- tion of 20 m/s2.
a. what is the acceleration of a different speck of dust that is twice as far from the center of the disk?
Learn more about centripetal acceleration at;
brainly.com/question/6217221
Answer:
valance electrons
Explanation:
the lines between the atoms represent the number of valance electron. simple isn't it.