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leonid [27]
2 years ago
15

Find x: (4x^2-25)^2-9(2x-5)^2=0

Mathematics
1 answer:
Feliz [49]2 years ago
6 0

Answer:

(4 {x}^{2}  - 25)^{2}  - 9(2x - 5)^{2}  = 0 \\  \\  {(4 {x}^{2}  - 25)} (4 {x}^{2} - 25)   - 9(2x - 5)(2x - 5) = 0 \\  \\( 16 {x}^{4}  - 200 {x}^{2}    + 625) - 9(4 {x}^{2}  - 20x + 25) = 0 \\  \\ (16 {x}^{4}  - 200 {x}^{2} + 625) + ( - 36 {x}^{2}  + 180x - 225) = 0 \\  \\ 16 {x}^{4}   - 236 {x}^{2}  + 180x + 400 = 0 \\  \\ 4(x + 1)(x + 4)(2x - 5)^{2}  = 0 \\  \\ x + 1 = 0 \\ x =  - 1 \\  \\ x + 4 = 0 \\ x =  - 4 \\  \\  {(2x - 5)}^{2}  = 0 \\ 2x - 5 = 0 \\ 2x = 5 \\ x =  \frac{5}{2}

I hope I helped you^_^

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Answer:

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Step-by-step explanation:

7 0
2 years ago
Given log4(3) =0.7925 and log4(5) =1.1610, use log properties to find log4(300).
Ede4ka [16]

Answer:

4.1145

Step-by-step explanation:

You can use the following formula to solve this kind of problems,

log_{a}(b)  +  log_{a}(c)  =  log_{a}(bc)

So, let's start of with log4_(300). Since the question have already gave log4_(3) =0.7925 and log4_(5) =1.1610. It means that you have to split the 300 into the simplest form where almost all of the numbers are 3 and 5.

log_{4}(300)  =  log_{4}(4 \times 5 \times 3 \times 5)  \\  =  log_{4}(4)  + log_{4}(5)  + log_{4}(3)  + log_{4}(5)  \\   = 1 + 1.1610 + 0.7925 + 1.1610 \\  = 4.1145

5 0
2 years ago
Please answer <br>Find the product.<br>(7m^2-3m-7)(m^2-7m-6)​
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Step-by-step explanation:

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5&lt;-3x+8 solve and graph the question
bearhunter [10]

Answer:

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Step-by-step explanation:

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This solution has no solutions because when you do a substitution method you might end up getting rid of the variable and left with a constant.
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