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leonid [27]
3 years ago
15

Find x: (4x^2-25)^2-9(2x-5)^2=0

Mathematics
1 answer:
Feliz [49]3 years ago
6 0

Answer:

(4 {x}^{2}  - 25)^{2}  - 9(2x - 5)^{2}  = 0 \\  \\  {(4 {x}^{2}  - 25)} (4 {x}^{2} - 25)   - 9(2x - 5)(2x - 5) = 0 \\  \\( 16 {x}^{4}  - 200 {x}^{2}    + 625) - 9(4 {x}^{2}  - 20x + 25) = 0 \\  \\ (16 {x}^{4}  - 200 {x}^{2} + 625) + ( - 36 {x}^{2}  + 180x - 225) = 0 \\  \\ 16 {x}^{4}   - 236 {x}^{2}  + 180x + 400 = 0 \\  \\ 4(x + 1)(x + 4)(2x - 5)^{2}  = 0 \\  \\ x + 1 = 0 \\ x =  - 1 \\  \\ x + 4 = 0 \\ x =  - 4 \\  \\  {(2x - 5)}^{2}  = 0 \\ 2x - 5 = 0 \\ 2x = 5 \\ x =  \frac{5}{2}

I hope I helped you^_^

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3 years ago
What is the simplified form of x+6 over x+4 + x-3 over 3
Zigmanuir [339]
1 Cancel <span>33</span>
<span>x+\frac{6}{x}+4+x-1<span>x+<span><span>​x</span>​<span>​6</span><span>​​</span></span>+4+x−1</span></span>
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<span>(x+x)+\frac{6}{x}+(4-1)<span>(x+x)+<span><span>​x</span>​<span>​6</span><span>​​</span></span>+(4−1)</span></span>
3 Simplify
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PLEASE HELP with3,4,5,6 <br> DUE IN 20 min
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Answer:

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4.

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3 years ago
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Mademuasel [1]

Answer:

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Step-by-step explanation:

Given in the y direction:

v₀ = 0 ft/s

Δy = 75 ft

a = 32 ft/s²

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Δy = v₀ t + ½ at²

(75 ft) = (0 ft/s) t + ½ (32 ft/s²) t²

t = 2.165 s

Given in the x direction:

Δx = 480 ft

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3 years ago
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