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3 years ago

15

Find x: (4x^2-25)^2-9(2x-5)^2=0

1 answer:

Feliz [49]3 years ago

6 0

Answer:

$(4 {x}^{2} - 25)^{2} - 9(2x - 5)^{2} = 0 \\ \\ {(4 {x}^{2} - 25)} (4 {x}^{2} - 25) - 9(2x - 5)(2x - 5) = 0 \\ \\( 16 {x}^{4} - 200 {x}^{2} + 625) - 9(4 {x}^{2} - 20x + 25) = 0 \\ \\ (16 {x}^{4} - 200 {x}^{2} + 625) + ( - 36 {x}^{2} + 180x - 225) = 0 \\ \\ 16 {x}^{4} - 236 {x}^{2} + 180x + 400 = 0 \\ \\ 4(x + 1)(x + 4)(2x - 5)^{2} = 0 \\ \\ x + 1 = 0 \\ x = - 1 \\ \\ x + 4 = 0 \\ x = - 4 \\ \\ {(2x - 5)}^{2} = 0 \\ 2x - 5 = 0 \\ 2x = 5 \\ x = \frac{5}{2}$

I hope I helped you^_^

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alexandr402 [8]

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4 years ago

A pole that is 2.6 m tall casts a shadow that is 1.03 m long. At the same time, a nearby tower casts a shadow that is 46.25 m lo

photoshop1234 [79]

Answer:

Therefore the height of the tower is 116.75 m.

Step-by-step explanation:

Given that a pole that is 2.6 m tall casts a shadow that is 1.03 m long.

Here the height of a object directly proportional to the shadow. It means

Height of the object ∝ shadow

Height of the object= k.shadow

[k is the proportional constant.]

$\Rightarrow \frac{h}{s} =k$ [Height of object is denoted by h and shadow is denoted by s]

Then,

$\frac{h_1}{s_1} =k$ [h₁ is the height of the pole and s₁is the length of the shadow]

Again for the tower

$\frac{h_2}{s_2}=k$ [h₂ is the height of the tower and s₂ is the length of the shadow]

Therefore,

$\frac{h_1}{s_1}=\frac{h_2}{s_2} =k$

$\Rightarrow\frac{h_1}{s_1}=\frac{h_2}{s_2}$ ............(1)

Given $h_1 = 2.6 m$ , $s_1=1.03m$ and $s_2=46.25m$

Putting the value of $h_1,s_1$ and $s_2$ equation (1)

$\frac{2.6}{1.03}=\frac{h_2}{46.25}$

$\Rightarrow h_2 \times1.03= 2.6\times 46.25$ [cross multiplication]

$\Rightarrow h_2 = \frac{2.6\times 46.25}{1.03}$

$\Rightarrow h_2= 116.75$

Therefore the height of the tower is 116.75 m.

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3 years ago

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Answer:

Step-by-step explanation:

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8 + 6 + 6 = 20 marbles in total

the probability of the marble being white is 6/20 or 3/10

so the probabilty of the marble NOT being white is 1 - (3/10) = 7/10

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3 years ago

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Vadim26 [7]

The answer is C. 14
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3 years ago

In ΔJKL, the measure of ∠L=90°, JL = 80, KJ = 89, and LK = 39. What is the value of the sine of ∠J to the nearest hundredth

emmainna [20.7K]

Given:

In ΔJKL, m∠L=90°, JL = 80, KJ = 89, and LK = 39.

To find:

The value of sine of ∠J.

Solution:

In a right angle triangle,

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3 years ago