Answer:
Area segment = 3/2 π - (9/4)√3 units²
Step-by-step explanation:
∵ The hexagon is regular, then it is formed by 6 equilateral Δ
∵ Area segment = area sector - area Δ
∵ Area sector = (Ф/360) × πr²
∵ Ф = 60° ⇒ central angle of the sector
∵ r = 3
∴ Area sector = (60/360) × (3)² × π = 3/2 π
∵ Area equilateral Δ = 1/4 s²√3
∵ The length of the side of the Δ = 3
∴ Area Δ = 1/4 × (3)² √3 = (9/4)√3
∴ Area segment = 3/2 π - (9/4)√3 units²
The answer is 257.08m. Explanation: you know that one side of the square in the middle is 50m. This is the same as the diameter of one of the half circles on each side. The perimeter of a circle is the formula C=2(pi)r, where r is the radius. Dividing 50 by two will get you the size of the radius, then just plug it into the equation to find the perimeter of both rounded sides (a full circle). The two circular sides equal 157.08m, so then you just need to add the flat sides, which are both 50m since they’re congruent. 157.08m + 50m + 50m = 257.08m, so the perimeter of the shape is 257.08m.
The supplementary angle to 69 degrees would be 111 DEGREES.
because it has to add up to 180 (69 + 111 = 180)
9 and 12 are slope-intercept form and 10 and 11 are point-slope form
