In order to complete the series of substitution values from $35 to $45 in increments of $2.50, follow these steps:
- Input $35 in B21.
- Highlight B21 to B26.
- Go to the Home tab.
- Go to the Editing ribbon.
- Click on Fill.
- Click on Series.
- Step Value = 2.50
- Stop Value = 45.
- Click Okay.
<h3>How can you complete a series of Substitution values?</h3>
First input the value you are to start with in the cell you are to start with. In this case that means putting $35 in Cell B21.
Highlight B21 to B26 and then go to the Home tab. Go to the Editing ribbon at the bottom right and click on Fill. Then go to Series and input the step value as 2.50 and the stop value as 45. Click okay and the range will appear.
Find out more on spreadsheet functions at brainly.com/question/1395170.
Answer:
Explanation:
Since all of the items in the array would be integers sorting them would not be a problem regardless of the difference in integers. O(n) time would be impossible unless the array is already sorted, otherwise, the best runtime we can hope for would be such a method like the one below with a runtime of O(n^2)
static void sortingMethod(int arr[], int n)
{
int x, y, temp;
boolean swapped;
for (x = 0; x < n - 1; x++)
{
swapped = false;
for (y = 0; y < n - x - 1; y++)
{
if (arr[y] > arr[y + 1])
{
temp = arr[y];
arr[y] = arr[y + 1];
arr[y + 1] = temp;
swapped = true;
}
}
if (swapped == false)
break;
}
}
Answer:
SyntaxError.
Explanation:
https://www.quora.com/In-Python-what-kind-of-error-is-returned-by-the-following-code-e-g-NameError-ValueError-IOError-etc-def-my_func-n1-n2-return-n1-n2-my_func-1-2-3 sorce site
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brainlest plz</h2>
Answer:
earth planet rest orbit moon
Answer:
The program in C++ is as follows:
#include <iostream>
using namespace std;
int perimeter(int side1, int side2, int side3){
return side1+side2+side3;
}
struct Triangle {
int side1; int side2; int side3;
};
int main(void) {
int side1, side2, side3;
cout<<"Sides of the triangle: ";
cin>>side1>>side2>>side3;
struct Triangle T;
T.side1 = side1;
T.side2 = side2;
T.side3 = side3;
cout << "Perimeter: " << perimeter(T.side1,T.side2,T.side3) << endl;
return 0;
}
Explanation:
See attachment for complete code where comments are as explanation
