Answer: 120.9 grams
Explanation:
Given the question : How many grams are in 3.67 moles of Lithium cyanide?
Chemical formula of lithium cyanide = LiCN
Molar mass of LiCN: Li = 6.941 ; C = 12, N = 14
LiCN = (6.941 + 12 + 14). = 32.941 g/mol
(Gram of substance / mole of substance) = (molar mass of substance / one mole)
(Gram of substance / 3.67) = (32.941 / 1)
= gram * 1 = 3.67 * 32.941
Gram of substance = 120.89347
= 120.9 grams
Answer:
<h2>0.92 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question we have
mass = 16.1 g
volume = 17.5 mL
We have the final answer as
<h3>0.92 g/mL</h3>
Hope this helps you
Answer: 310K
Explanation:
Given that:
Volume of Chlorine gas V = 10.2L
Temperature T = ?
Pressure P = 1.83 atm
Number of moles of chlorine gas N = 0.734 moles
Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
1.83atm x 10.2L= 0.734 moles x 0.0821 atm L K-1 mol-1 x T
18.67atm L = 0.0603 atm L K-1 x T
T = (18.67atm L / 0.0603 atm L K-1)
T = 309.8K (Round up to 310K)
Thus, the temperature of the chlorine gas is 310 kelvin
Answer:
B. compound
Explanation:
A pure substance can be an element, which consists of only one type of atom and cannot be broken down by a chemical change, or a compound, which consists of two or more types of atoms.
