<u>Answer:</u> The pH of the buffer is 4.61
<u>Explanation:</u>
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[\text{conjuagate base}]}{[\text{acid}]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5B%5Ctext%7Bconjuagate%20base%7D%5D%7D%7B%5B%5Ctext%7Bacid%7D%5D%7D%29)
We are given:
= negative logarithm of acid dissociation constant of weak acid = 4.70
![[\text{conjuagate base}]}](https://tex.z-dn.net/?f=%5B%5Ctext%7Bconjuagate%20base%7D%5D%7D)
= moles of conjugate base = 3.25 moles
![[\text{acid}]](https://tex.z-dn.net/?f=%5B%5Ctext%7Bacid%7D%5D)
= Moles of acid = 4.00 moles
pH = ?
Putting values in above equation, we get:
Hence, the pH of the buffer is 4.61
Answer:
an isotope has the same number of protons but a different number of neutrons than the other atoms of the same element.
Answer:
They are Weaker than a chemical
<h2>bond</h2>
corrected by the one in the comment section
Answer:
Explanation:Because of the delocalised electrons exposed above and below the plane of the rest of the molecule, benzene is obviously going to be highly attractive to electrophiles - species which seek after electron rich areas in other molecules.
M=n(pie)/RT
n=osmotic pressure(1.2 atm)
M=molar of the solution
R=gas constant(0.0821)
T= temperature in kelvin 25+273
M=[1.2atm /(0.0821L atm/k mol x 298k)]=0.049mol L
M= moles of the solute/ litres of solution(250/1000)
0.049= y/0.25
moles of solute is therefore =0.01225mol
molar mass=33.29 g/0.01225mol=2.7 x10^3g/mol
