Which option can be classified as a pure substance

Andreas93 [3]

Answer:

1. The process of removal of the dissolved salts from sea/ocean water is called desalination.

2.Well and Spring water contains dissolved impurities but not suspended imputites or germs because they have been filtered through different layers of soil.Thus, well water and spring water is pure and safe to drink.

3 Rain water is the purest form of water.

4.The interconversion of the three state of water aldo occurs in nature which is known as water cycle.

5. a) Due to water cycle, it rains. Raining is very important because agricultural production depends on it.

b) Controls the climatic conditions all over the world.

Explanation:

4 0

3 years ago

On occasion, it has been found that the oxidation of borneol doesn't go to completion (possibly because of poor stirring or insu

seraphim [82]

Answer:

Check the explanation

Explanation:

Here, Nitrogen (N) undergoes oxidation and Chlorine (Cl) undergoes reduction.

To answer your question:

N is oxidized from an oxidation number of -3 to an oxidation number of -1.

Cl is reduced from oxidation number of +1 to an oxidation number of -1.

Now,

Borneol should have a lower Rf because of boiling point.

3 0

3 years ago

Please answer this correctly!

Marina CMI [18]

Answer:

International is the answer duh

4 0

2 years ago

If a solution contains all the solute it can hold at a given temperature, it is said to be ________________

iren [92.7K]

The answer is B) saturated

3 0

3 years ago

Read 2 more answers

A sample of carbon dioxide gas has a density of g/L at a pressure of 0.889 atm and a temperature of 55.0 °C. Assume ideal behavi

gladu [14]

Answer:

163.5 °C

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 686 mL.

Initial temperature (T1) = 55 °C.

Final volume (V2) = 913 mL

Initial pressure (P1) = final pressure (P2) = 0.889 atm

Final temperature (T2) =.?

Next, we shall convert celsius temperature to Kelvin temperature.

This can be done as shown below:

Temperature (K) = Temperature (°C) + 273

T(K) = T (°C) + 273

Initial temperature (T1) = 55 °C.

Initial temperature (T1) = 55 °C + 273

Initial temperature (T1) = 328 K

Next, we shall determine the new temperature of the gas.

Since the pressure is constant, we shall determine the new temperature as follow:

V1/T1 = V2 /T2

Initial volume (V1) = 686 mL.

Final volume (V2) = 913 mL

Initial temperature (T1) = 328 K

Final temperature (T2) =.?

V1/T1 = V2 /T2

686/328 = 913/T2

Cross multiply

686 x T2 = 328 x 913

Divide both side by 686

T2 = (328 x 913)/686

T2 = 436.5 K

Finally, we shall convert Kelvin temperature to celsius temperature.

This can be done as shown below:

Temperature (°C) = Temperature (K) – 273

T (°C) = T(K) – 273

T(K) = 436.5 K

T (°C) = 436.5 – 273

T (°C) = 163.5 °C

Therefore, the temperature of the gas sample is 163.5 °C.

5 0

3 years ago