Please help me with this problem.
1 answer:
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Answer:
3.9 mi/h
Step-by-step explanation:
If the boy is rowing perpendicular to the current, the two vectors form a right triangle.
AB represents the downstream current, BC is the speed across the river, and AC is the ground speed of the boat
AC^2 = 2.4^2 + 3.1^2 =5.76 + 9.61 = 15.37
AC = sqrt(15.37) = 3.9 mi/h
The boat's speed over the ground is 3.9 mi/h.
Solve each equation for y and then the slope is m and y-intercept is b as in:
So, if you do that, you'll get (remember, this is <em>after</em> solving for y):
1. m = -6, b = -2
2. m = 5, b = -1
3. m = -5/3, b = 5
4. m = 0, b = -1/4
5. m = -1, b = -3
6. m = 3, b = -4
7. m = 1/2, b = -5/2
8. m = 7/2, b = 1
Hope this helps.
So, if you do that, you'll get (remember, this is <em>after</em> solving for y):
1. m = -6, b = -2
2. m = 5, b = -1
3. m = -5/3, b = 5
4. m = 0, b = -1/4
5. m = -1, b = -3
6. m = 3, b = -4
7. m = 1/2, b = -5/2
8. m = 7/2, b = 1
Hope this helps.