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Ghella [55]
3 years ago
11

(1 point) 6 cards are drawn at random without replacement from a standard deck. Be accurate to 7 decimal places. a) Find the pro

bability that all the cards are hearts. b) Find the probability that all the cards are face cards. Note: Face cards are kings, queens, and jacks. c) Find the probability that all the cards are even. (Consider aces to be 1, jacks to be 11, queens to be 12, and kings to be 13)
Mathematics
1 answer:
V125BC [204]3 years ago
7 0

Answer:

a) P=0.0000843

b) P=0.0000454

c) P=0.0066113

Step-by-step explanation:

6 cards are drawn at random without replacement from a standard deck.

a) We calculate the probability that all the cards are hearts.

We calculatethe number of possible combinations:

C^{52}_6=\frac{52!}{6!(52-6)!}=20358520

We calculate the number of favorable combinations:

C_6^{13}=\frac{13!}{6!(13-6)!}=1716

Therefore, the probability is

P=\frac{1716}{20358520}\\\\P=0.0000843

b) We calculate the probability that all the cards are face cards.

We calculatethe number of possible combinations:

C^{52}_6=\frac{52!}{6!(52-6)!}=20358520

We calculate the number of favorable combinations:

C_6^{12}=\frac{12!}{6!(12-6)!}=924

Therefore, the probability is

P=\frac{924}{20358520}\\\\P=0.0000454

c) We calculate the probability that all the cards are even.

We calculatethe number of possible combinations:

C^{52}_6=\frac{52!}{6!(52-6)!}=20358520

We calculate the number of favorable combinations:

C_6^{24}=\frac{24!}{6!(24-6)!}=134596

Therefore, the probability is

P=\frac{134596}{20358520}\\\\P=0.0066113

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Step-by-step explanation:

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Can someone help me please
kifflom [539]

9514 1404 393

Answer:

  {Segments, Geometric mean}

  {PS and QS, RS}

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Step-by-step explanation:

The three geometric mean relationships are derived from the similarity of the triangles the similarity proportions can be written 3 ways, each giving rise to one of the geometric mean relations.

  short leg : long leg = SP/RS = RS/SQ   ⇒   RS² = SP·SQ

  short leg : hypotenuse = RP/PQ = PS/RP   ⇒   RP² = PS·PQ

  long leg : hypotenuse = RQ/QP = QS/RQ   ⇒   RQ² = QS·QP

I find it easier to remember when I think of it as <em>the segment from R is equal to the geometric mean of the two segments the other end is connected to</em>.

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  segments PS and QS, gm RS

  segments PS and PQ, gm PR

  segments PQ and QS, gm QR

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