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chubhunter [2.5K]
3 years ago
7

Write the fraction 7/10 as a sum of fraction three different ways

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
A . 2/10 + 5/10= 7/10
B. 3/10 + 4/10= 7/10
C. 6/10 + 1/10 =7/10
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a teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te
natka813 [3]

The question is incomplete. The complete question is

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shown in the below-mentioned figure shows the results of the test.

Which class should get the reward, and why?

- The 2nd-period class should get the reward. They have the highest score, a perfect 100.

- The 2nd-period class should get the reward. They have a higher median.

- The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

- The 4th-period class should get the reward. Their lowest score is an outlier and should be thrown out.

The box plot shown in the question provides the information that
In 2nd period the minimum of the data is 77, first quartile is 78, median of the data is 89, third quartile is 92 and the maximum of the data is 100.
Hence, the mean of the results of 2nd period is

\frac{77+78+89+92+100}{5}=87.2

In 2nd period the minimum of the data is 72, first quartile is 83, median of the data is 89, third quartile is 96 and the maximum of the data is 98.

Hence, the mean of the results of the 4th period is

\frac{72+83+89+96+98}{5}=87.6

Hence, obviously, the 4th period is having more mean.

Moreover, we can observe that if more of the marks are on the higher side the average will automatically be more. Hence, as the first and the third quartiles are more on the 4th-period, so the average marks for the 4th period must be better.

So, just by observing the box plot, we can give the statement that  "The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class. "

Therefore, the 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

Learn more about box plots here-

brainly.com/question/1523909

#SPJ10

6 0
1 year ago
What is 2+2•67/19•34+1
snow_lady [41]

2+2*67/19*34+1

2+\frac{134}{19}(34)+1

2+\frac{4556}{19}+1

\frac{4594}{19}+1

=\frac{4613}{19}

Hope this helps!

Thanks!

-Charlie

7 0
2 years ago
Read 2 more answers
What is the difference of the means of the distributions? 15 30 45 60
valentina_108 [34]

Answer:

The difference is 15.

Step-by-step explanation:

30-15=15

45-30=15

60-45=15

5 0
2 years ago
Read 2 more answers
you had a party at your house. after the party, you had 0.5 of a liter of soda remaining. how many milliliters of soda did you h
photoshop1234 [79]
A liter is 1000 mL so half of 1000 = 500

500 mL is the answer!
6 0
3 years ago
A glacier advances toward the sea 0.004 mile anually. In 2010 the front of the glacier is 6.9 miles from the mouth of the sea. H
olchik [2.2K]

You know where the glacier is now, and how far it moves in
one year.  The question is asking how close to the sea it will be
after many years.

Step-1 ... you have to find out how many years

Step-2 ... you have to figure out how far it moves in that many years

Step-3 ... you have to figure out where it is after it moves that far

The first time I worked this problem, I left out  the most important
step ... READ the problem carefully and make SURE you know
the real question.  The first time I worked the problem, I thought
I was done after Step-2. 

============================

Step-1:  How many years is it from 2010 to 2030 ?

               (2030  -  2010)  =  20 years .


Step-2:  How far will the glacier move in 20 years ? 

               It moves 0.004 mile in 1 year.

              In 20 years, it moves 0.004 mile 20 times

              0.004 x 20  =  0.08 mile


Step-3: How far will it be from the sea after all those years ?

              In 2010, when we started watching it, it was 6.9 miles
              from the sea.

              The glacier moves toward the sea.
               In 20 years, it will be  0.08 mile closer to the sea.
               How close will it be ?

               6.9 miles  -  0.08 mile  =  6.82 miles  (if it doesn't melt)

7 0
3 years ago
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