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Stels [109]
2 years ago
13

Can you help me with this

Mathematics
1 answer:
storchak [24]2 years ago
7 0

Answer:

c

Step-by-step explanation:

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X=7 <br><br> X=4<br><br> Please someone help ?
Katarina [22]

Step-by-step explanation:

×=4 is the answer thank you

6 0
3 years ago
3. WRITE Write a paragraph explaining the order of the steps that you would take to
polet [3.4K]
Upon first glance of an equation one must look first for parenthesis and solve the contents therein. Next one would need to identify and simplify exponents. Once these steps are well done one needs to look at the whole equation from left to right and solve for any multiplication or division problems and solve them in the order in which they appear. Next one must again look at the equation left to right and solve for any addition or subtraction in the order that they appear within the equation.
6 0
3 years ago
What is the area of the shaded region below?<br> 7 m<br> 30 m<br> 7 m<br> 21 m
Rama09 [41]

Answer:

322.28

A

Step-by-step explanation:

Area of the rectangle

L = 30

W = 21

Area = 30 * 21

Area = 630

Area of the circles

Radius = 7 m

Area = pi r^2

Area = 3.14 * 7^2

Area = 153.86 m^2

Area of both circles = 307.72

Area of the Shaded Region

Area of shaded region = area of the rectangle - area of 2 circles.

Area of Shaded Region = 630 - 307.72

Area of Shaded Region = 322.28

5 0
3 years ago
Please help me asap
pentagon [3]

Answer:

No, it isn't linear because the graph is not a straight line.

Step-by-step explanation:

(see picture of graph)

Linear means a straight line, and these points do not form a line, so it is not linear. You can also calculate this by finding the slope between each point and the previous.

8 0
3 years ago
Read 2 more answers
Write the equation of the parabola whose focus is (4,0) and directrix at y = 2
goldfiish [28.3K]

Answer:

\left ( x-4 \right )^{2}+\left ( y-0 \right )^{2}=\left ( y-2 \right )^{2}

Step-by-step explanation: We know that distance from a point on the parabola and  focus is equal to their distance from a the directrix. Let (x, y) be the point,

So,

\sqrt{\left ( x-4 \right )^{2}+\left ( y-0 \right )^{2}}=\frac{\left | y-2 \right |}{1}

\left ( x-4 \right )^{2}+\left ( y-0 \right )^{2}=\left ( y-2 \right )^{2}. This is the required equation.

3 0
4 years ago
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