1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
taurus [48]
3 years ago
8

What is the d/dx tan^3x

Mathematics
1 answer:
Bad White [126]3 years ago
6 0
\frac{d}{dx}(tan^{3}x) = \frac{d}{dx}(tanx)^{3}
= 3(tanx)^{2} \cdot sec^{2}x

\therefore \frac{d}{dx}(tan^{3}x) = 3tan^{2}x \cdot sec^{2}x
You might be interested in
JIMMMMMM
Vitek1552 [10]
>= means greater than or equal to
<= means less than or equal to

---------------------------------------------

Part A

The graph of y >= -3x+3 will have a solid boundary line and the shading will be above the boundary line.

The boundary line y = -3x+3 has a negative slope so it moves down as you read it from left to right. It goes through the points (0,3) and (1,0)

--------------

The graph of y < (3/2)x - 6 will have a dashed or dotted boundary line. The shading is below the boundary.

The graph y = (3/2)x-6 goes through the two points (0,-6) and (2,-3)

--------------

If you graph both y >= -3x+3 and y < (3/2)x - 6 together, you get what you see in the attached image. This solution shaded region is the result of the overlapping prior shaded regions. 

---------------------------------------------

Part B

Plug (x,y) = (-6,3) into each inequality to see if we get a true inequality or not

For the first inequality we have
y >= -3x+3
3 >= -3*(-6)+3
3 >= 18+3
3 >= 21
which is false. The value 3 is not larger or equal to 21. So right off the bat we know that (-6,3) is NOT a solution. It is NOT in the solution region.

Let's check the other inequality just for the sake of completeness
y < (3/2)x - 6
3 < (3/2)*(-6) - 6
3 < -9 - 6
3 < -15
this is also false. The value -15 is smaller than 3, since it is to the left of 3

We're given more evidence that (-6,3) is NOT in the solution area. It is outside of both shaded areas. 

7 0
3 years ago
Read 2 more answers
-(j-7)+3=5 what is j?
Fofino [41]
The answer is 5/ j=5
7 0
2 years ago
Assume a random sample of size n is from a normal population. Assume a single sample t test is used to for hypothesis testing. T
valentinak56 [21]

Answer:

True

Step-by-step explanation:

Type I and Type II are not independent of each other - as one increases, the other decreases.

However, increases in N cause both to decrease, since sampling error is reduced.

A small sample size might lead to frequent Type II errors, i.e. it could be that your (alternative) hypotheses are right, but because your sample is so small, you fail to reject the null even though you should.

5 0
3 years ago
Can anyone please help me with question need help please ​
Ivanshal [37]

Step-by-step explanation:

there is no reason in maths only the method

4 0
3 years ago
Ab+ac-a²-bc ??????????????????​
babunello [35]
Answer: ab+a-b
ab+ac-a2
CLT( collect like terms)
ab+a2+ac-bc
ab+a-b.

Hope this is correct



6 0
3 years ago
Other questions:
  • Find the area of the polygon defined by the coordinates (0, -5), (-5, 0), (-15, -20), and (-20, -15). A) 90 square units B) 110
    9·2 answers
  • On a vocabulary list within a study guide, definitions should be written
    12·2 answers
  • 5+5orienwjiwinwjeuejnsjsineneje​
    12·1 answer
  • Line p passes through A(-2, -4) and has a slope of -1/2. What is the standard form of the equation for line p?
    8·1 answer
  • Four less than half a number is 15. Find a number.
    14·2 answers
  • Plz someone help ASAP! thanks​
    12·1 answer
  • Plz answer! only if you are correct. do NOT answer just for points i’ll report you lol.
    11·1 answer
  • Find the area. 14 m 4.5 m 4.5 m 9m 12 m 3 m 3 m <br><br>plzzz help meeee​
    9·1 answer
  • Evaluate the expression.<br><br> 24÷(−4)+(−2)⋅(−5)=
    14·2 answers
  • Here this is a giveaway free 100 i started back
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!