Question

What is the d/dx tan^3x

Answer 1

$\frac{d}{dx}(tan^{3}x) = \frac{d}{dx}(tanx)^{3}$
$= 3(tanx)^{2} \cdot sec^{2}x$

$\therefore \frac{d}{dx}(tan^{3}x) = 3tan^{2}x \cdot sec^{2}x$