3 years ago

What is the d/dx tan^3x

1 answer:

6 0

$\frac{d}{dx}(tan^{3}x) = \frac{d}{dx}(tanx)^{3}$
$= 3(tanx)^{2} \cdot sec^{2}x$

$\therefore \frac{d}{dx}(tan^{3}x) = 3tan^{2}x \cdot sec^{2}x$

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