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PIT_PIT [208]
3 years ago
11

When is it possible to see the chromosphere region of the Sun?

Chemistry
1 answer:
sattari [20]3 years ago
8 0

The chromosphere is the third and the lowermost layer of the sun and appears bright red. This chromosphere region is visible only during the total solar eclipse. Thus, option B is correct.

<h3>What is a solar eclipse?</h3>

A total solar eclipse is an event in which the new moon is in between the Earth and the Sun resulting in the formation of the dark shadow on the Earth's surface.

During this eclipse, the chromosphere region of the sun is visible as it was hidden by the photosphere before the eclipse. It shines bright red and yellow as the spectral line of the hydrogen alpha is emitted.

Therefore, option B. the chromosphere region is visible only during the total solar eclipse.

Learn more about the eclipse here:

brainly.com/question/11390151

#SPJ1

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ahrayia [7]
Lithium forms a +1 ion because it loses one electron, making the ratio of electrons:protons unbalanced by losing one electron. the ratio is now 2e:3p.

Oxygen forms a -2 ion because of a different reason. It gains 2 electrons rather than losing them.
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The air bags in cars are inflated when a collision triggers the explosive, highly exothermic decomposition of sodium azide (NaN3
Oksanka [162]

Answer : The mass of NaN_3 required is, 166.4 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = 113 L

n = number of moles N_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 85^oC=273+85=358K

Putting values in above equation, we get:

1.00atm\times 113L=n\times (0.0821L.atm/mol.K)\times 358K

n=3.84mol

Now we have to calculate the moles of sodium azide.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 3 mole of N_2 produced from 2 mole of NaN_3

So, 3.84 moles of N_2 produced from \frac{2}{3}\times 3.84=2.56 moles of NaN_3

Now we have to calculate the mass of NaN_3

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

Molar mass of NaN_3 = 65 g/mole

\text{ Mass of }NaN_3=(2.56moles)\times (65g/mole)=166.4g

Therefore, the mass of NaN_3 required is, 166.4 grams.

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Calculate the frequency if the wavelength of energy is 6.5 x 10^-7m
melamori03 [73]
The answer to the problem is
69.55
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Which group, metals or nonmetals, has the greatest chance to gain electrons and to become negative ions?
tatyana61 [14]
It would be non-metals
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