Answer: 9000 - 1 significant figure
Explanation: Since you are multiplying, the number with the least amount of significant figures determines the number of significant figures in the answer. The number 9 has 1 significant figure and 1025 and has 4 significant figures so 9 has the fewest significant figures, meaning your answer will be 1 significant figure.
Answer:
The answer to your question is limiting reactant = Fe
Explanation:
Data
moles of Fe = 2
moles of O₂ = 6
Process
1.- Write the balanced chemical reaction
Fe + O₂ ⇒ Fe₂O₃
Reactants Elements Products
1 Fe 2
2 O 3
4Fe + 3O₂ ⇒ 2Fe₂O₃
Reactants Elements Products
4 Fe 4
6 O 6
2.- Use the balanced chemical reaction to determine the limiting reactant.
Theoretical proportion of reactants 4 moles Fe / 3 moles O₂ = 1.33
Experimental proportion of reactants = 2 moles Fe/6 moles O₂ = 0.333
3.- Conclusion
As the experimental proportion was lower than the theoretical we conclude that the amount of Fe was lower in the experiment which is the limiting reactant.
<span>Dominos are similar in that the movement of one domino causes others to fall, which is a chain reaction. The problem with dominos is that one domino usually causes one other domino to fall which is a linear chain reaction (unless the dominos are set to knock over more dominos as in a fan shape). In nuclear fission of Uranium the reaction is an exponential growth chain reaction. The fission of one atom of U235 releases two or three neutrons which can cause other atoms to split which each release 2-3 neutrons and so on. In this way one split causes 3 splits which cause 9 splits which cause 27 splits and so on. A better analogy is shown in the video where the mousetrap releases 2 balls which set off 2 traps which set off 4 traps.</span>
Answer:
0.0125 moles of NaOH are present
Explanation:
Molarity, M, is an unit of concentration widely used in chemistry. Is defined as the ratio between moles of solute (In this case, NaOH) and liters of solution.
250.0mL are = 0.250L of solution. As the molarity of the solution is 0.05M = 0.05moles / 1L, the moles present are:
0.250L * (0.05moles / 1L) =
<h3>0.0125 moles of NaOH are present</h3>