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scZoUnD [109]
2 years ago
14

Least common denominator again please lol. Sorry I keep asking so many questions, but hey, I guess it means you guys get more po

ints and brainliest lol

Mathematics
1 answer:
Olenka [21]2 years ago
8 0

Answer:

hope it's help u

Step-by-step explanation:

the \: lcm \: of \: 2 \: and \: 9 \: is \: 18.so \: the \: lcd \: is \: 18 \\ \frac{11}{2}  =   \frac{11 \times 9}{2 \times 9}  =  \frac{99}{18 }  \\  \frac{1}{9}  =  \frac{ 1\times 2 }{9 \times 2}  =  \frac{2}{18}  \\ \frac{99}{18}  >  \frac{2}{18}

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SIMPLE AND CLEAR i hate brainly
HACTEHA [7]

Im not sure just give me a minute

7 0
3 years ago
Classify the following based on sides and angles.​
matrenka [14]

Answer:

D. right; scalene

Step-by-step explanation:

As you can see in the diagram you have a 90, 50, and 40 degrees angles. Because one of the angles is equal to 90 degrees (a right angle) this triangle can be classified as a right triangle.

No congruent sides are shown.... That means it's a scalene.

3 0
3 years ago
Solve for t <br> 1000=(10000)/(5+1245(e^-.97t))
vladimir2022 [97]
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6 0
3 years ago
The third grade students go on a field trip. Of the 321 students there are 5 more girls than boys. How many girls are there? How
eduard
First you would take 321 and subtract 5
316
they you would divide by 2
158
there are 158 boys 
to find the # of girls take 158 and add 5
163
8 0
3 years ago
Compute the Taylor expansion of order n=2 of the function sin(xy) at x=0 and y=0
artcher [175]

Answer:

f(x, y) = Sin(x*y)

We want the second order taylor expansion around x = 0, y = 0.

This will be:

f(x,y) = f(0,0) + \frac{df(0,0)}{dx} x + \frac{df(0,0)}{dy} y + \frac{1}{2} \frac{d^2f(0,0)}{dx^2} x^2 +\frac{1}{2} \frac{d^2f(0,0)}{dy^2}y^2  + \frac{d^2f(0,0)}{dydx} x*y

So let's find all the terms:

Remember that:

\frac{dsin(ax)}{dx}  = a*cos(ax)

\frac{dcos(ax)}{dx} = -a*cos(ax)

f(0,0) = sin(0*0) = 1.

\frac{df(0,0)}{dx}*x = y*cos(0*0)*x = x*y

\frac{df(0,0)}{dy} *y = x*cos(00)*y = x*y

\frac{1}{2} \frac{d^2f(0,0)}{dx^2}*x^2 =  -\frac{1}{2}  *y^2*sin(0*0)*x^2 = 0

\frac{1}{2} \frac{d^2f(0,0)}{dy^2}*y^2 =  -\frac{1}{2}  *x^2*sin(0*0)*y^2 = 0

\frac{d^2f(0,0)}{dxdy} x*y = (cos(0*0) -x*y*sin(0*0))*x*y = x*y

Then we have that the taylor expansion of second order around x = 0 and y = 0 is:

sin(x,y) = x*y + x*y + x*y = 3*x*y

6 0
3 years ago
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