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Vinvika [58]
3 years ago
10

The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = 3/2 . What is the value of b?

Mathematics
2 answers:
kvasek [131]3 years ago
6 0
The axis of symmety is the x value of the vertex

to find the x value of the vertex of ax^2+bx+c=0
x value=-b/2a

3x^2+bx+4=0
3/2=vertex

-b/2(3)=3/2
-b/6=3/2
times 6
-b=18/2
-b=9
times -1
b=-9
gregori [183]3 years ago
5 0

the correct answer is B=-9

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Vlada [557]
We want to find \displaystyle{  \frac{dy}{dx}, for

            \displaystyle{ y=(x^2+2)^3(x^3+3)^2.

Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:

                                  (fg)'=f'g+g'f.

Thus,

 y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3

Answer: A)      3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3.



8 0
3 years ago
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Rus_ich [418]

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6 0
3 years ago
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Vaselesa [24]

Answer:

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Step-by-step explanation:

Because of this fact:

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So his credit rating is considered as Good ( 660- 749)

Have a good day

8 0
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Answer:

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The numbers are differ by 6, 9 and next will be differ by 12 resulting the next no. 0.

7 0
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If B(x)=-1,then what is x​
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Step-by-step explanation:

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