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notsponge [240]

3 years ago

10

Milan spent a total of $70 at the grocery store. Of this amount, he spent $63 on fruit. What percentage of the total did he spen

d on fruit?

2 answers:

Ilia_Sergeevich [38]3 years ago

8 0

63/70 =0.9
0.9 * 100 = 90%

so 90% of the total he spent

bekas [8.4K]3 years ago

7 0

95% Is your answer c:

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What is the diameter of a circle with a circumference of 56 inches?

Anna [14]

Answer:

17.83in

Step-by-step explanation:

8 0

2 years ago

At a grocery store, the price of a watermelon is determined by how many pounds the watermelon weighs. The price of a watermelon

Alexxx [7]

Answer:

$p=0.60w$

Step-by-step explanation:

Let

p ----> the price of a watermelon in dollars

w ---> the weight of a watermelon in pounds

In this problem we have a proportional relationship

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem

$p=kw$

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$k=\frac{4.38}{7.3}=\$0.60\ per\ pound$

substitute in the equation

$p=0.60w$

7 0

3 years ago

I dont get this at all

zhenek [66]

Continuous vs discrete is if you can count vs. measure the results. For example: you can run 13. 5 miles but you can't have 13.5 dogs. Miles (measurable) are continuous while dogs (countable) are discrete.

Qualitative results are when a result is not a number, and qualitative is when the result is a number. For example: if you're doing a lab and a result is either going to be "blue" or "green", that's qualitative, since those aren't number values. However, if you were measuring distance, that would be qualitative, since you would get a result of "6 meters" or "2.5 inches", which are numerical values.

The scale of measurement are the units in which you are measuring something it. For example: distance has units of inches, feet, miles, etc... and weight has units of grams, kilograms, tons, etc...

Hope this helps! -Alex :)

6 0

3 years ago

Read 2 more answers

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

a.

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

3 years ago

If p=5 and q=6, evaluate the following expression:2p+3q/4

suter [353]

Answer:

7

Step-by-step explanation:

Substitute in numbers : 2(5)+3(6) /4

Combine Like Terms : 10+18/4 = 28/4

Answer : 7

8 0

3 years ago