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Sergio [31]
2 years ago
14

A charitable organization holds a canned food drive to benefit the local food bank. The number of cans collected by the voluntee

rs of the organization as they came in are 2, 6, 12, 16, 2, 6, 13, 17, 3, 8, 13, 19, 4, 10, 14, 19, and 5.
Pls help. I need the first and third quartile and the median
Mathematics
1 answer:
kirill115 [55]2 years ago
8 0

Answer:

Step-by-step explanation:

Minimum: 2

Quartile Q1: 4.5

Median: 10

Quartile Q3: 15

Maximum: 19

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Given The following Graph:<br><br> a.)Evaluate f(0). <br> b.) Solve for f(x) = -3
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Answer:

see explanation

Step-by-step explanation:

a

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Consider an obtuse triangle with two angles measuring 95°. What must be true?
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Step-by-step explanation:

7 0
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Read 2 more answers
How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x​
ivanzaharov [21]

\Large \mathbb{SOLUTION:}

\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes}  \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}

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