<h3>
Answer: Choice B) real and integer</h3>
Explanation:
The set of integers is {..., -3, -2, -1, 0, 1, 2, 3, ...} basically its the set of positive and negative whole numbers, including 0 as well. The set of whole numbers is {0, 1, 2, 3, 4, ...} so any positive number that does not a fractional or decimal part. The value 0 is included in the set of whole numbers. The natural numbers is {1, 2, 3, 4, ...} so it is the set of whole numbers but we kicked out 0 from this set. The set of natural numbers is also called the set of counting numbers.
If we take any two integers and divide them then you'll get a rational number. You cannot have zero in the denominator, but you can have any other integer. For example, 2 and 3 divide to get the fraction 2/3 which is a rational number. Numbers that we cannot express as a fraction of two integers are said to be irrational. An example of this is pi = 3.14 which is irrational. We cannot write pi as a ratio of two integers. One approximation is pi = 22/7, but this doesn't represent pi exactly. Any integer itself is rational. Something like -13 can be written as -13/1, so we cannot say -13 is irrational. That rules out choice A. Choice C is ruled out because negative numbers aren't natural numbers. The same can be said about -13 not being part of the whole number set {0, 1, 2, 3, 4, ...} so choice D is also false.
Answer:
x = -12
Step-by-step explanation:
2(x+1)-3x=14 (expand parenthesis i.e PEDMAS rule)
2x + 2 - 3x = 14 (bring all x terms to one side and numbers to the other; subtract 2 from both sides)
2x - 3x = 14 - 2 (evaluate each side)
-x = 12 (multiply both sides by -1)
x = -12
Answer:
-7 is the answer!! :) hope this helps
