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3 years ago

Pls help will give brainliest aubviously

Mathematics

1 answer:

QveST [7]3 years ago

4 0

I believe it is the second one... I think = is for numbers only.

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Solve the quadratic equation numerically (using tables of x- and y- values). x squared + 5 x + 6 = 0 a. x = -3 or x = -2 c. x =

sineoko [7]

Answer:

Step-by-step explanation:

I did it on math class

6 0

2 years ago

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What are these negative fractions converted to positive ones (I suck at math so I need an explanation): -5/6, -7 3/8, -3/11

Paraphin [41]

Answer:

multiply each by -1

-5/6 x -1 = 5/6

-7 3/8 x -1 = 7 3/8

-3/11 x -1 = 3/11

Step-by-step explanation:

6 0

2 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

2 years ago

How many years does it take to earn a million dollars if you are paid $30 an hour and work 35 hours a week for 50 weeks a year

AnnyKZ [126]

This is a Multiple Step problem.Which means that you have to do a few steps before you get the answer.First,you do,30x35,then the answer,(product)to that,you multiply that answer to 50,then find out the answer to that,then divide 1 million by that answer,then you will get the year.

6 0

2 years ago

Can anyone please help me!

Alexxx [7]

Answer:

Step-by-step explanation:

(4)(−2)+10

=−8+10

5 0

2 years ago

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