Answer:
5x=13.5
Step-by-step explanation:
Well, we know that 1x=2.7. So, if we want 5x we need to multiply 2.7*5 becuase 1x=2.7, so 5x=2.7*5.
Multiply. 2.7*5=13.5
So, 5x=13.5.
Hope this helps!
Answer:
-10
Step-by-step explanation:
subtract 4 from both sides
divide by 2
Answer:
2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So



has a pvalue of 0.7881.
1 - 0.7881 = 0.2119
So 21.19% of the students use the computer for longer than 40 minutes.
Out of 10000
0.2119*10000 = 2119
2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.
That is the answer , i looked it up for you my self :)
The first step to solve this problem is to compute first for
the area of the bigger rectangle:
A = LW
A = 12m (10m)
A = 120 m^2
Next step is to find the area of the smaller rectangle:
A = LW
A = 7m (2m)
A = 14 m^2
The last step is to deduct the area of the smaller rectangle
to the area of the larger rectangle:
Area of larger rectangle – Area of the smaller rectangle =
Area of the shaded region
120 m^2 – 14 m^2 = 106 m^2
Therefore, the area of the shaded region is 106 square
meters.