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Vlad1618 [11]
3 years ago
8

Find the surface area of the composite figure rounded to the nearest hundredths. Use the pi button.

Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0

Answer:

To find the area of composite figures and use area of a circle to find the radius.  Estimate the radius of the circle with the given area.

Step-by-step explanation:

I only say how you can founded

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Solve: 10(0.5x- 2) = -3x + 20 + 8x
eduard

Answer: no solution

Step-by-step explanation:

6 0
2 years ago
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Answer this in two minutes
gregori [183]

Hey there! :)

Answer:

y = x - 3.

Step-by-step explanation:

Given:

Slope = 1

Point on line: (8, 5)

Plug these into the formula y = mx + b, where:

m = slope

x = x coordinate of point

y = y coordinate of point

5 = 1(8) + b

5 = 8 + b

Subtract both sides by 8:

5 - 8 = 8 -8 + b

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Rewrite the equation:

y = x - 3.

4 0
3 years ago
The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance betw
shusha [124]
We know that
circumference=2*pi*r-------> r=circumference/(2*pi)
circumference=30 in
r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
the radius of a <span>standard basketball is 4.77 in
</span>
<span>the distance between the ball and the rim is equal to
</span>radius of a basketball rim minus radius of a a standard basketball  
radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in<span>

</span>
the distance between the ball and the rim=[9-4.77]------> 4.23 in

the answer is
4.23 in
3 0
3 years ago
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Which object is the best conductor of electricity?
gulaghasi [49]

Answer:

D. Metal Nail

a good conductor is something metalic which can easily make electricity pass through it.

BRAINLIEST PLEASE

5 0
2 years ago
G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.
vova2212 [387]

Answer:

▢ $\overline{DG}$ ≅ $\overline{FG}$

▢ $\overline{DG}$ ≅ $\overline{BG}$

▢ $\overline{GE}$ bisects \displaystyle ∠DEF

▢ $\overline{GA}$ bisects \displaystyle ∠BAF

Step-by-step explanation:

As you can see, angles \displaystyle BAF and \displaystyle DEF form two half-kites, which you should know have <em>two</em><em> </em><em>pairs of</em><em> </em><em>congruent</em><em> </em><em>sides</em>, therefore segments \displaystyle GA and \displaystyle GE are what you call angle bisectours, which is why segments \displaystyle FG, \displaystyle DG, and \displaystyle BG are congruent.

I am joyous to assist you at any time.

4 0
3 years ago
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