Question

What are the potential rational zeros in this polynomial y = 2x3 - 11x2 +18x - 9?

Answer 1

Answer:

1; 1.5; 3.

Step-by-step explanation:

1) the potential zeros are the numbers which the '-9' can be divided by: ±1; ±3; ±9;

2) according to the definition above: x=1. Then the given equation can be re-written

2x³-11x²+18x-9=0; ⇔ (x-1)(2x²-9x+9)=0. Then

3) re-written again as

$(x-1)(x-\frac{3}{2})(x-3)=0;$

4) the required zeros are: 1; 1.5 and 3.