Alright my friend so if she ran 1/4 a mile in just 3 minutes then her overall time will be 12 minutes because she still has 3 more to go so basically it'll be 3 x 4 = 12

3 0

3 years ago

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Solve for x use the completing the square method x^2+6x=5

Mrac [35]

Answer:

$x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}$

Step-by-step explanation:

$x^{2}$ +6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power: 3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

$x^{2}$ +6x+9-9-5=0

we have:

$(x+3)^{2}$ -9-5=0

$(x+3)^{2}$ = 14

lets apply square root on both sides of the equation:

$\sqrt{(x+3)^{2}}=\sqrt{14}$

we know:

$\sqrt{a^{2}} = abs(a)$

so we have:

abs(x+3)= $\sqrt{14}$

from where two solutions are obtained

$x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}$

finally we have:

$x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}$

5 0

3 years ago

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Show work

nika2105 [10]

Let's call the distance from the beach to the playground x.
Let's call the distance from the stand to the parking lot z.
Let's call the base of the biggest triangle in the picture (from the parking lot to the left) y.

Recall the pythagorean theorem: the sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse.

There are three right triangles we can work with.

Triangle with sides 48, x and z. Here z is the hypotenuse so we get the equation $x^{2} + 48^{2} = z^{2}$

Triangle with sides 27, x and y. Here y is the hypotenuse so we get $27^{2} + x^{2} = y^{2}$

Triangle with sides z, y and (48+27). Here (48+27) is the hypotenuse so we get $y^{2} + z^{2} = (27+48)^{2}$ . That is, $y^{2} + z^{2} = 5625$

We have 3 equations and 3 unknowns (x, y and z). So let's take the last equation: $y^{2} + z^{2} = 5625$ and replace $z^{2}$ and $y^{2}$ using expressions that contain an expression in terms of x from the first two equations we came up with.

That gives us: $48^{2} + x^{2} + x^{2} + 27^{2} =5625$ which we solve for x as follows:

$2 x^{2} + 3033 =5625
2x^{2} =2592
 x^{2} =1296
x=36$

Now that we know x we can substitute 36 for x into the equation $48^{2} + x^{2} = z^{2}$ and solve for z as follows:
$48^{2} + 36^{2} = z^{2} 
2304+1296=z^{2} 
3600=z^{2} 
z=60$

This means that the distance from the beach to the parking lot is 36 m and the distance from the stand to the parking lot is 60 m.

4 0

3 years ago

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