Solve for x: -3x + 3 < 6 x>-1 x<-1 x<-3 x>-3

Mathematics

1 answer:

Triss [41]3 years ago

5 0

Answer:

D is the correct answer

Step-by-step explanation:

first you subtract the 3 from the left side and add it to the right side. then you divide both side by negative 3 and flip the less than sign to a greater than sign

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I don't get how to solve it

skelet666 [1.2K]

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3 years ago

The tens digit is three less than the units digit. If the digits are reversed, the sum of the reversed number and the original n

muminat

Answer:

Original number is 47

Step-by-step explanation:

Given: The tens digit is three less than the units digit. If the digits are reversed, the sum of the reversed number and the original number is 121.

To find: the original number

Solution:

Let x denotes digit at ones place.

As the tens digit is three less than the units digit,

Digit at tens place = $x-3$

Original number = $10(x-3)+x=11x-30$

When digits are reversed,

Reversed number = $10x+(x-3)=11x-3$

As the sum of the reversed number and the original number is 121,

$11x-30+11x-3=121\\22x-33=121\\22x=154\\x=\frac{154}{22}\\=7$

So,

original number = $11x-30=11(7)-30=77-30=47$

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3 years ago

the vertex of this parabola is (2,-1). When the x-value is 5 the y-value is 0.what is the coefficient of the squared expression

weeeeeb [17]

1/9
Here's the proper explanation:
Since the vertex is (2,-1), the original equation will look like this: y=a*(x-2)^2-1
When the substitution happens we get to this:
0=a*(5-2)^2-1 then 1=a*(5-2)^2 -> 1=a*9
So, a=1/9! Written in another form:
1/9x^2-4/9x+4/9-1

Hope could help :)

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Step-by-step explanation: 9 + 9 = 9

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