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Vladimir79 [104]
2 years ago
7

What is the area of this quadrilateral?

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
5 0

Answer:

D

Step-by-step explanation:

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Kayla bought a car that's price was reduced by 34%. The original price for the car was $16,000. How much did she spend on the ca
aliya0001 [1]

The price was reduced by 34%, so she paid 100-34 = 66% of the original price.

16,000 x 0.66 = 10,560

She paid $10,560

8 0
3 years ago
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6 m
dimulka [17.4K]

Answer:

51.63m^3

Step-by-step explanation:

The figure is made up of a rectangle, triangle and a semi circle

Area of the figure = Area of triangle + rectangle + semicircle

Area of the triangle = 1/2 * base * height

Area of the triangle = 1/2 * 3 * 5

Area of the triangle = 15/2

Area of the triangle = 7.5m^3

Area of the rectangle = Length * Width

Area of the rectangle = 6 * 5

Area of the rectangle = 30m^2

Area of the semicircle = πr²/2

Area of the semicircle = π(3)²/2

Area of the semicircle = 3.14(9)/2

Area of the semicircle = 3.14 * 4.5

Area of the semicircle = 14.13m^2

The area = 30 + 14.13+7.5

Area of the figure = 51.63m^3

7 0
3 years ago
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If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3
yulyashka [42]

Hello,

L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\

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3 years ago
Muad can lift 129.6 pounds and Samara can lift 135.25 pounds. How much more weight can Samara lift?
notka56 [123]

Answer:5.29 pounds

Step-by-step explanation:

135.25 -129.6

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3 years ago
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What digit is in the ten thousands place 1.03098 show how you got this and I will mark brainiest
Luden [163]
The 0 is in the ten thousands
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3 years ago
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