The question is slightly weird.
You have a piece of line, and its ends are 'P' and 'Q'.
All of the points on the paper that are the same distance
from 'P' and 'Q' are the points that form the line that bisects
segment-PQ and is perpendicular to it.
Other words: The line that is perpendicular to PQ at its mid-point.
Other words: The perpendicular bisector of segment PQ.
All of the points in space that are the same distance from
'P' and 'Q' are the points that form the plane perpendicular
to segment PQ at its mid-point.
Answer:
focus and belive on your self
Step-by-step explanation:
Answer:
Step-by-step explanation:
If the projectile is hitting something on the ground, it has a height of 0. Sub in a 0 for the h and factor to solve for t:
Factor out a -16t to get
0 = -16t(t - 2.5) which means that either t = 0 or t = 2.5
I'd say it has to be t = 2.5, don't you? ; )
Answer:
y + 6.5 =-5 (x - 7.1)
Step-by-step explanation:
We can use the point slope equation of a line
y -y1 = m(x-x1)
We have a point and a slope
y - - 6.5 = -5 (x - 7.1)
y + 6.5 =-5 (x - 7.1)
