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Pavlova-9 [17]
2 years ago
13

Throughout the lecture, the teacher speaks about the defintion of " Science ". From the choices below, which option supports the

wording mentioned in the lecture ? a. Observation, inferencing, predicting, classifying and making models c. One or more senses to gather info b. Science is using different skills to make models d. None of these Please select the best answer from the choices provided A B C D
SAT
2 answers:
notka56 [123]2 years ago
7 0

Answer:

A

:)Hope this helps

Explanation:

SCORPION-xisa [38]2 years ago
5 0

Answer:

B) Science is using different skills to make models

Explanation:

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Find the value of e the margin of error for c
vodomira [7]

Answer:

f

Explanation:

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3 years ago
A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin
Alekssandra [29.7K]

The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

  • 131.6 N/C
  • 12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}

Which gives;

\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C

\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C

Which gives;

\vec{E}_1 = \mathbf{21.6 \, N/C  \cdot \hat x +  28.8 \, N/C \hat y}

\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C

Therefore;

\vec  {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)

\vec  {E} = \mathbf{\left( -128.4 \, N/C  \right) \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)}

The magnitude of the net electric field is therefore;

E = \sqrt{(-128.4^2 + 28.8^2)} ≈ 131.6

  • The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>

(b) The direction of the net electric field at the origin.

  • The \ direction \ is \ arctan \left(\dfrac{28.8}{-128.4} \right) \approx \underline{ 12.6^{\circ}} \ above \ the \ negative \ x-axis

Learn more about electric field strength here:

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2 years ago
What are the elements of a good study environment? Check all that apply. It is well lit. Resources are near. It is quiet. A frie
victus00 [196]
Resources are near and it is quiet and it is clutter free ? I’m sorry if I’m wrong those are the only ones that make it a good study environment
3 0
3 years ago
Read 2 more answers
In khoomii the performer seems to sing more than one of which of the following at a time
Yuri [45]

In khoomii the performer seems to sing more than one note at a time.

<h3>What is the singing about?</h3>

A khoomii singer is known to be a person that often makes or produces two tones at the same time and this is one that is often done via the process that entails the manipulating the mouth cavity and the changing of the position of the human tongue.

The khöömei are known to be the most popular aspect of Tuvan throat singing as they are known to have a kind of a low-mid to that of mid- range normal voice.

In this style, it is made up of two or three harmonics see between one and two octaves.

Hence, In khoomii the performer seems to sing more than one note at a time.

Learn more about performer from

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4 0
2 years ago
The dnsity of aluminum is 2. 70 g/mL. if the mass of a piece of aluminum is 244 grams, what is the volume of the aluminum
joja [24]
27.0 g

Explanation:
The density of a substance tells you the mass of exactly one unit of volume of said substance.
In your case, aluminium is said to have a density of
density Al
=
2.70 g
.
cm
−
3
This tells you that every
1 mL
of aluminium has a mass of
2.70 g
.
All you have to do now is use the density of aluminium as a conversion factor to go from cubic centimenters of aluminium to grams
10.0
cm
3
⋅
2.70 g
1
cm
3
=
27.0 g
−−−−−
The answer is rounded to three sig figs.
8 0
3 years ago
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