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2 years ago

{(-2/3)^-2}^2 can someone pls help me in this

Mathematics

1 answer:

anzhelika [568]2 years ago

8 0

The value of the expression given in the task content is; 81/16.

<h3>What is the value of the expression?</h3>

According to the task content;

We are required to determine the value of the expression given in the task content.

{(-2/3)^-²}^²

= {(-2/3)^-⁴

= (-3/2)-⁴

= 81/16

Therefore, the value of the expression given in the task content is; 81/16.

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Answer:

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Step-by-step explanation:

$\frac{-2+i}{-4-5i}$

Apply complex arithmetic rule: $\frac{a + bi}{c + di} = \frac{(c-di) (a + bi)}{(c-di) (c + di)} =\frac{(ac+bd)+(bc-ad)i}{c^2+d^2}$

$a=-2,b=1, c=-4,d=-5$

$=\frac{\left(-2\left(-4\right)+1\cdot \left(-5\right)\right)+\left(1\cdot \left(-4\right)-\left(-2\right)\left(-5\right)\right)i}{\left(-4\right)^2+\left(-5\right)^2}$

Refine:

$=\frac{3-14i}{41}$

Rewrite $\frac{3-14i}{41}$ in standard complex form: $\frac{3}{41} - \frac{14}{41}i$

Final answer: $\frac{3}{41} - \frac{14}{41}i$

Hope I helped! If so, may I get Brainliest and a Thanks?

Thank you, Have a good one! =)

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