$\displaystyle\\\text{The equation is:}\\\\13^2-x^2=15^2-(14-x)^2\\\\13^2-x^2=15^2-(14^2-28x+x^2)\\\\13^2-x^2=15^2-14^2+28x-x^2)\\\\-x^2+x^2-28x=15^2-14^2-13^2\\\\-28x=225-196-169\\ \\-28x=-140~~~\Big|~\cdot(-1)\\\\28x=140\\\\x=\frac{140}{28}\\ \\\boxed{\bf x=5}$

4 0

3 years ago

The difference between the length L and width W of one face of a box is 4 inches. The face has a perimeter of 52 inches. Find th

sertanlavr [38]

The sum of length and width is half the perimeter, so that sum is 26 inches.

If length and width were equal, they would both be 26/2 = 13 inches. Adding 2 inches to one dimension and subtracting 2 inches from the other will keep the sum the same and make them differ by 4 inches.

The length and width are 15 inches and 11 inches, respectively.

5 0

3 years ago

Inverse operationsare pairs of mathematical manipulations in which one operation undoes the action of the other—for example, add

Valentin [98]

The answer is you are looking for is 0.36

3 0

2 years ago

Read 2 more answers

How do you do this because it's complicated

Mice21 [21]

FAM U JUST NEED TO BELIEVE JUST BELIEVE USE THE POWER OF DANK MEMES THEN YOUR DREAMS WONT BE DREAMS