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2 years ago

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An accountant rents three notebook computers for temporary workers to use during tax season. The total rental amount is $2750. T

he accountant makes monthly payments of $1100. How much interest for the accountant pay on the rental?

1 answer:

FinnZ [79.3K]2 years ago

6 0

I think its 1$
hope this help u

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What is the minimum value of C = 7x + 8y, given the constraints: 2x + y ≥ 8, x + y ≥ 6, x ≥ 0, y ≥ 0. A. 32 B. 42 C. 46 D. 64

marshall27 [118]

Answer: The minimum value of C is 46.

Step-by-step explanation:

Since, Here, We have to find out Min C = 7x+8y

Given the constraints are $2x+y\geq 8$ -------(1)

$x+y \geq 6$ ------------- (2)

$x \geq 0$ , $y \geq 0$ -------- (3)

Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)

And, $2\times 0+0\geq 8$ ⇒ $0\geq 8$ ( false)

Therefore the area of line 1) does not contain the origin.

For equation 2) x-intercept, (6, 0) and y-intercept (0,6)

And, $0+0\geq 6$ ⇒ $0\geq 6$ ( false)

Therefore the area of line 2) does not contain the origin.

Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)

At A≡(0,8) , C= 64

At E≡(2,4), C= 46

At B≡(6,0), C= 42

Thus at B, C is minimum, And its minimum value = 42

5 0

2 years ago

Read 2 more answers

Find m∠U.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.

olga2289 [7]

Answer:

Answer:

50.2

Step-by-step explanation:

$ut = \sqrt{ {6}^{2} + {5}^{2} } \\ \sqrt{36 + 25} \\ \sqrt{61 } \\ using \: cosine \: rule \\ cos \: u = \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times \sqrt{61} } \\ \\ = \frac{25 + 61 - 36}{78} \\ \\ = \frac{50}{78 } \\ \cos \: u = 0.64 \\ m∠U. = 50.2$

7 0

1 year ago

What is the volume of this cone? Use 3.14 for pi and round your answer to the

emmasim [6.3K]

So I use the formula hopefully these steps work

7 0

2 years ago

How many times greater is The total area of Russia than the total area of Finland? Finland total area is 3.4 x 10 to the 5th pow

Luden [163]

Answer:

The answer to your question is Russia is 50 times greater than Finland.

Step-by-step explanation:

Data

Finland area = 3.4 x 10⁵ km²

Russia area = 1.7 x 10⁷ km²

Proportion = ?

Process

1.- Just divide the Russia's area by the Finland's area.

Proportion = $\frac{Finland's area}{Russia's area}$

Proportion = $\frac{1.7 x 10^{7} }{3.4 x 10^{5} }$

Porportion = 50

6 0

2 years ago

A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye

Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{x}=n\mu$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{x}=\sqrt{n}\sigma$

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

$\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)$

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

$P (\sum X \leq 100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}$

$=P(Z$

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0

2 years ago