23.22%:
2.5 L in mL : 2.5 * 1000 = 2500 mL
23.22 g ----------- 100 mL
? g ------------- 2500 mL
m = 2500 * 23.22 / 100
m = 58050 / 100
m = 580,5 g
Answer:
0.400 mL
Explanation:
Hello, the dilution factor (in folds) is given by:
Thus, the sample volume with three significant figures is given by:
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Answer:
The heat of vaporisation of methanol is "3.48 KJ/Mol"
Explanation:
The amount of heat energy required to convert or transform 1 gram of liquid to vapour is called heat of vaporisation
When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.
Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is =
= 3.48 KJ
So, the heat of vaporization
Therefore, the heat of vaporization of methanol is 3.48KJ/Mol
Mercury atoms have 80 electrons and 80 protons with 122 neutrons in the most abundant isotope. Under standard conditions mercury is a shiny, heavy, silvery liquid. It is the only metal that is liquid at room temper