Answer:
it cannot !!
Explanation:
a chemical reaction MUST occur to separate a compound! :)
Answer:
B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2
Explanation:
Hello,
In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.
Moreover, in the other reactions, copper (A.), sodium (C. and D.) remain with the same initial oxidation state, +2 and +1 respectively.
Regards.
Hey there :)
<em>Q</em><em>u</em><em>e</em><em>s</em><em>t</em><em>i</em><em>o</em><em>n</em><em>:</em><em> </em><em>How many km are in 5.6mm? </em>
<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>3 </em>
<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>-6 </em>
<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>-3 </em>
<em>=</em><em>></em><em> </em><em>5.6x10</em><em>^</em><em>6</em>
<em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em><em>-</em>
<em>E</em><em>x</em><em>p</em><em>l</em><em>a</em><em>n</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em>:</em><em>-</em>
By using the formula-
As 1 with 6 zeros, we convert it into exponential form.
As this above value is fraction type, we can do the reciprocal, thus, the exponent gets a negative value.
Now combine with given question.
Answer:
72.22 g
Explanation:
975 mL Mercury× 13.5 g/mL = 72.22 g
Answer: C. CO₂ and H₂O
Explanation:
Combustion reactions produce carbon dioxide and water.