Answer:
That the isotope H-1 is the most abundant in nature.
Explanation:
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In this case, since the average atomic mass of an element is computed considering the mass of each isotope and the percent abundance each, for hydrogen we would set up something like this:
Moreover, since the isotope notation H-1 and H-2 means that the atomic mass of H-1 is 1 amu, that of H-2 is 2 amu and the average one is 1.0079 amu, we can infer that the most of the hydrogen in nature is H-1 as the most of it composes the average hydrogen atom.
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Answer:
+8 J/mol
Explanation:
The following were obtained from the question:
Mole of the compound = 3 moles
Heat Energy used = 24J
Hreaction =?
The heat of reaction is the energy released or absorb during a chemical reaction. It is can obtained mathematically by the following equation:
Hreaction = Heat energy/mole
With the above equation, we can easily find the Hreaction for the question given as follow:
Hreaction = Heat energy/mole
Hreaction = 24J / 3mol
Hreaction = 8 J/mol
Since the compound used the energy, the Hreaction is +8 J/mol
Answer is: 0,133 mol/ l· atm.
T(chlorine) = 10°C = 283K.
p(chlorine) = 1 atm.
V(chlorine) = 3,10 l.
R - gas constant, R = 0.0821 atm·l/mol·K.
Ideal gas law: p·V = n·R·T
n(chlorine) = p·V ÷ R·T.
n(chlorine) = 1atm · 3,10l ÷ 0,0821 atm·l/mol·K · 283K = 0,133mol.
Henry's law: c = p·k.
k - <span>Henry's law constant.
</span>c - solubility of a gas at a fixed temperature in a particular solvent.
c = 0,133 mol/l.
k = 0,133 mol/l ÷ 1 atm = 0,133 mol/ l· atm.
[A]0= Initial concentration
t1/2= half life
[A]= final concentration
k= rate constant
