Step-by-step explanation:
as the velocity is not constant over time, we actually have to integrate v(t) over the interval 0<=t<=5 to get the distance.
v(t) = 60×ln(t + 1)
V(t) = 60 × integral(ln(t + 1)) between 0 and 5.
integral(ln(t + 1)) = (t + 1)ln(t + 1) - t + C
V(t) = 60 × ((t + 1)ln(t + 1) - t + C)
the distance traveled between t = 0 and t = 5 is then
60 × ((5 + 1)ln(5 + 1) - 5 + C) - 60 × ((0 + 1)ln(0 + 1) - 0 + C) =
= 60×(6ln(6) - 5 + C) - 60×(1ln(1) + C) =
= 60×(5.750556815... + C) - 60×C =
= 60×5.750556815... = 345.0334089... ≈ 345 km
Answer:
12^x
Step-by-step explanation:
Absolute. Value. Of. |12^x-8|. Is. 12^x + 8
12^x + 8= 2^3. So. 12^x. +8.=8
12^x+8-8=8-8
12^x=0. Left. With. 12^x?
Easy
if x is the number
sqrt x is between 17 and 18
17<√x<18
squaer the whole thing
289<x<324
x could be 300
it could be sqrt of 300
√300=10√3
one is 10√3
Answer:
I belive it is c
Step-by-step explanation:
If your 2 means "u squared" then
Just do 8-42=-34
The answer is -32u^2
I use ^ to show exponents