Solve the system of equations.

2 answers:

7 0

Solve the system of equations.
12x + 3y = 12
-6x +y = -26

A) (-3,9)
B (-6, -9)
© (-3,8)
D (3, -8)

12x + 3y = 12
2(-6x +y = -26)

12x + 3y = 12
-12x + 2y = -52

—-now x cancels out

5y/5 = -40/5

y = -8

The answer should be D. Let me know if you got it right.

Ainat [17]2 years ago

7 0

Answer:

12X +3y =12.....equation 1

-6x +y = -26....equation 2

putting the value

in equation 2 multiply by 2

12x +3y =12

-12x +2y = -52

____________

5y = -40

y = -40%5

y = -8

putting the value of y in equation 1

12x + 3y = 12

12x + 3× -8 =12

12x -24 =12

12x =12 + 24

12x =36

x =36%12

x=3

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