Solve the system of equations.
2 answers:
Solve the system of equations.
12x + 3y = 12
-6x +y = -26
A) (-3,9)
B (-6, -9)
© (-3,8)
D (3, -8)
12x + 3y = 12
2(-6x +y = -26)
12x + 3y = 12
-12x + 2y = -52
—-now x cancels out
5y/5 = -40/5
y = -8
The answer should be D. Let me know if you got it right.
Answer:
12X +3y =12.....equation 1
-6x +y = -26....equation 2
putting the value
in equation 2 multiply by 2
12x +3y =12
-12x +2y = -52
____________
5y = -40
y = -40%5
y = -8
putting the value of y in equation 1
12x + 3y = 12
12x + 3× -8 =12
12x -24 =12
12x =12 + 24
12x =36
x =36%12
x=3
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