All categories

2 years ago

Step by step explanation please. i want to try to understand it.

Mathematics

2 answers:

alexira [117]2 years ago

7 0

Answer:

Step-by-step explanation:

For a single cylinder:

radius (r) = 3 in (Given)

height (h) = 8 in (Given)

It is given that: all the three cylinders are identical, means their radii and heights are equal.

Thus, the volume of composite figure will be equal to three times the volume of single cylinder.

Step-by-step explanation:

zhenek [66]2 years ago

3 0

Answer:

$V_{composite\: figure} =678.24\: in^3$

Step-by-step explanation:

For a single cylinder:

radius (r) = 3 in (Given)

height (h) = 8 in (Given)

It is given that: all the three cylinders are identical, means their radii and heights are equal.

Thus, the volume of composite figure will be equal to three times the volume of single cylinder.

$\implies V_{composite\: figure} =3(\pi r^2 h)$

$\implies V_{composite\: figure} =3(3.14\times (3)^2 \times 8)$

$\implies V_{composite\: figure} =3(226.08)$

$\implies V_{composite\: figure} =678.24\: in^3$

You might be interested in

The managers of franks snack shack buys hamburgers in packages of 30 and hamburger buns in packages of 24. He cannot buy part of

Andreas93 [3]

Answer:

He has to buy 4 packages of hamburgers in packages of 30 and 5 packages of hamburgers in packages of 24

Step-by-step explanation:

First we have to calculate the least common multiple (LCM) of 24 and 30

We will calculate the LCM of 24 and 30 by prime factorization method

24 = 2*2*2*3 = $2^{3} * 3^{1}$

30 = 2*3*5 = $2^{1} *3^{1}* 5^{1}$

LCM = $2^{3}* 3^{1}*5^{1}$

LCM = 120

So number of hamburger buns = 120

Therefore, he must buy 120/24 = 5 packages of hamburgers in packages of 24 and he must also buy 120/30 = 4 packages of hamburgers in packages of 30

4 0

3 years ago

Choose the answer that represents the product below as an exponential

oksano4ka [1.4K]

Answer:

2^4

Step-by-step explanation:

2*2*2*2

There are four 2's multiplied together

2 is the base and 4 is the exponent

2^4

6 0

3 years ago

Read 2 more answers

Find the equation of the line that is parallel toy=32x−5

Alona [7]

Answer:

d/dx ( 32x - 5)

Step-by-step explanation:

i think this is right please tell me if its not

8 0

3 years ago

What is 11.52/128 show your work

grandymaker [24]

Answer:

The answer is

Step-by-step explanation:

11.5/128

First convert the decimal to an improper fraction

That's

$11.52 = \frac{288}{25}$

So we have

$\frac{288}{25} \div 128$

Change the division sign to multiplication sign and reverse the second number

That's

$\frac{288}{25} \times \frac{1}{128}$

Simplify

$\frac{288}{3200}$

Divide through by 32

The final answer is

$\frac{9}{100}$

Hope this helps you

6 0

3 years ago

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

3 years ago