What is positive correlation?

A fox leaves its den and travels 725 yards northeast, then 950 yards west. How far, in yards is the fox from its den

Alenkinab [10]

Answer:

1,675

Step-by-step explanation:

add it

7 0

3 years ago

Please help!! In all honesty, I am absolutely terrible at math. Sometimes I get it, but most of the time I'm brain dead.

astraxan [27]

Im like 90% positive that x= 13

8 0

3 years ago

Gabriel went to the grocery store and bought bottles of soda and bottles of juice. Each bottle of soda has 35 grams of sugar and

kupik [55]

Answer:

9 bottles of soda and 7 bottles of juice

Step-by-step explanation:

Let x be the number of bottles of soda purchased and y be the number of bottles of juice purchased.

1. Gabriel purchased 2 more bottles of soda than bottles of juice, then

$x=y+2$

2. Each bottle of soda has 35 grams of sugar, then there are 35x g of sugar in x bottles of soda.

Each bottle of juice has 10 grams of sugar, then there are 10y g of sugar in y bottles of juice.

In total, there are 35x+10y g of sugar.

All bottles collectively contain 385 grams of sugar, thus

$35x+10y=385$

3. Solve the system of two equations:

$\left\{\begin{array}{l}x=y+2\\ \\35x+10y=385\end{array}\right.$

Substitute the first equation into the second equation:

$35(y+2)+10y=385\\ \\35y+70+10y=385\\ \\35y+10y=385-70\\ \\45y=315\\ \\y=7\\ \\x=7+2=9$

7 0

3 years ago

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3. The adult men of the Dinaric Alps have the highest average height of all regions. The

ahrayia [7]

Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so X when Z = -0.253.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

5 0

2 years ago

Help with this math question

ZanzabumX [31]

That easy 56.8.895 because when u add all the steps u find u answer so don’t let it fool u

5 0

3 years ago

Read 2 more answers