All categories

2 years ago

A company manufactures glass paperweights in the shape of square base pyramids. The

Mathematics

1 answer:

Kipish [7]2 years ago

4 0

Answer:

12 in3

step by step exlpaination.

You might be interested in

An obtuse triangle has two angles 45 n 18 ,and a third unknown angle theta what's the value of the unknown angle

zlopas [31]

Answer:

An obtuse triangle has two angles 45 and 18. The value of the unknown angle is $117^{\circ}$

Solution:

Given that two angles of an obtuse triangle is 45 and 18.

Third angle is θ

We are asked to find the value of third unknown angle theta

According to angle sum property of triangle, sum of three angles of triangle is $180^{\circ}$

This means in our case sum of 45, 18 and θ should be $180^{\circ}$

$\begin{array}{l}{=>45+18+\theta=180} \\ {=>\theta=180-63=117^{\circ}}\end{array}$

Hence value of unknown third angle of an obtuse triangle is $117^{\circ}$

7 0

4 years ago

Write the fraction in simplest form of 6/20.

nikklg [1K]

$\dfrac{6}{20}=\dfrac{6:2}{20:2}=\dfrac{3}{10}$

8 0

3 years ago

adoni [48]

Answer:

i don't know sorry

Step-by-step explanation:

3 0

3 years ago

Solve for n. 19(n − 927) = 589

rewona [7]

Answer:

N=958

Step-by-step explanation:

19(n − 927) = 589

19n - 17,613 = 589

7 0

3 years ago

Read 2 more answers

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago