Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213
Answer:
4 and 6.
Step-by-step explanation:
There are 4 different grades represented, so for the first question, there are 4 ways that the students can sit if they must sit together by grade.
For the second question, there are 3 grades other than senior level, so it starts with 3 ways that the students can be seated. 3 ways x 2 students per way = 6 ways
Answer:
D. -3 for every 1 to the right, in goes down 3.
E. 0, the graph could represent no change over time.
F.
assume the point on the graph is the origin, you can graph these
(2,-4)
(1,-2)
(0,0)
(-1,2)
(-2,4)
(-3,6)
Step-by-step explanation: