Answer:
1/32v²sin2θ
Step-by-step explanation:
Given the expression r(theta) = 1/16v²sinθcosθ
According to double angle of trigonometry identity;
Sin2θ = sin(θ+θ)
Sin2θ = sinθcosθ + cosθsinθ
Sin2θ = 2sinθcosθ
sinθcosθ = sin2θ/2 ... **
Substituting equation ** into the question
1/16v²sinθcosθ = 1/16v²(sin2θ/2)
1/16v²sinθcosθ = 1/2×1/16v²(sin2θ)
1/16v²sinθcosθ = 1/32v²sin2θ
Hence using the double angle identity, the equivalent expression is 1/32v²sin2θ
I think it is 17 but i am not 100% accurate
Answer:
sin (330)
csc (60)
cos (390)
Step-by-step explanation:
Solve the trigonometric equation by isolating the function and then taking the inverse. Use the period to find the full set of all solutions
It's false. It's a product so...
Derivative of the first TIMES the second PLUS derivative of second TIMES the first.
Derivative of the first (x^3) = 3x^2
Times the second = 3x^2 * e^x
Derivative of the second = e^x (remains unchanged)
Times the first = e^x * x^3
So the answer would be (3x^2)(e^x) + (e^x)(x^3)
which can be factorised to form x^2·e^x(3 + x)
The correct answer would be D.
The mechanic would charge x amount per hour,
so it would look like:
x(time)
So lets say every hour was $5 and he worked on it for 5 hours, then it would be
$5(5)
hope this helps!
