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3 years ago

If you roll a dice 72 times, how many times do you expect to roll a 6?

2 answers:

3 0

Well every time you roll you have the same probability of get it 1 out of 6, so this question don't have a specific answer

Afina-wow [57]3 years ago

3 0

The probability of getting a 6 is P(6) = 1/6

If you roll the dice 72 times. the expectation value = P(6) x 72

or 1/6 x 72 = 12 times

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ASAP PLZ HELP WILL MARK BRAINLIST IF U WANT TO FIRST PERSON WHO ANSWERS RIGHT

photoshop1234 [79]

Answer:

15.0

Step-by-step explanation:

Square root entire equation (-8 - 7)^2 + (-5 + 4)^2

8 0

3 years ago

Read 2 more answers

120-2x=30, what’s x?

KiRa [710]

Step-by-step explanation:

-2x=30-120

-2x = -90

=x = -90/-2

=x = +45

4 0

3 years ago

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.9degreesf and a standard deviation of 0.67

trasher [3.6K]

Answer:

Step-by-step explanation:

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation = 0.67

n = number of samples = 103

From the information given, the population standard deviation is unknown hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 103 - 1 = 102

Since confidence level = 99% = 0.99, α = 1 - CL = 1 – 0.99 = 0.01

α/2 = 0.01/2 = 0.005

the area to the right of z0.005 is 0.005 and the area to the left of z0.005 is 1 - 0.005 = 0.995

Looking at the t distribution table,

z = 2.6249

Margin of error = 2.6249 × 0.67/√103

= 0.173

Confidence interval = 98.6 ± 0.173

This suggests that the mean body temperature could very possibly be

98.6degrees°F.

3 0

3 years ago

Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d

Olegator [25]

Answer:

The speed of the cars is $32 \frac{km}{h}$

Step-by-step explanation:

First we must first have the clear concept that $speed=\frac{distance}{time}$ or $s=\frac{d}{t}$

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: $s_{1}=s+1$ , $t_{1}=2$ and $d_{1}= d_{2}$

Car 1: $s_{2}=s-10$ , $t_{2}=3$ and $d_{1}= d_{2}$

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

$d_{1}=s_{1}*t_{1}$

$d_{1}=(s+1)*2$

$d_{1}=2s+2$

<em>Car 2</em>

$d_{2}=s_{2}*t_{2}$

$d_{2}=(s-10)*3$

$d_{2}=3s.30$

$d_{1}=d_{2}$

$2s+2=3s-30$

$2+30=3s-2s$

$32=s$

The speed of the cars is 32 km/hr

7 0

3 years ago

How do you simplify this?

lions [1.4K]

Answer:

sinA(cosA+sinA)*cosA

Step-by-step explanation:

(sinA(2cosA+sinA-cosA))/secA

sinA(cosA+sinA)/secA

sinA(cosA+sinA)*cosA

8 0

3 years ago