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Feliz [49]
3 years ago
7

Which statement describes the function y = axn when a = 1 and n is odd?

Mathematics
2 answers:
lubasha [3.4K]3 years ago
8 0

Answer:

B: The graph is symmetric about the origin

Step-by-step explanation:

you typed the question in wrong its ax^n not axn, which makes the answer above incorrect. this should be the right one on edge.

kiruha [24]3 years ago
4 0

Answer:

The graph is symmetric about the origin.

The graph does not pass through the origin.

Step-by-step explanation:

We're given:

  • the function y=axn
  • a = 1
  • n is odd

Because a = 1, then the given function can be rewritten as y = n.

  • The graph opens down

The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.

  • The graph is symmetric about the origin.

This is true, given the graph is a horizontal line.

  • The graph does not pass through the origin.

This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.

  • The graph has more than one x-intercept.

This would only be true when n = 0, and this isn't possible. So, no.

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seraphim [82]

Given:

The value of the function g(x) is −2 when x=−5 and is 5.7 when x=6.

To find:

The equation of the function.

Solution:

The value of the function g(x) is −2 when x=−5. It means the graph of function passes through (-5,-2).

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The equation of function g(x) that passes through (-5,-2) and (6,5.7) is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

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y+2=0.7(x+5)

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y=0.7x+3.5-2

y=0.7x+1.5

Therefore, the equation of function g(x) is y=0.7x+1.5.

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