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3 years ago

Consider this Expression.

Mathematics

2 answers:

MrMuchimi3 years ago

6 0

Answer:

The answer is -4x^2-7x-5

Step-by-step explanation:

Alex Ar [27]3 years ago

3 0

Answer:

Box 1 = -4

Box 2 = -3

Box 3 = -5

Step-by-step explanation:

-4 $x^{2}$ + 2x - 5(1 + x)

=> -4 $x^{2}$ + 2x - 5 - 5x

=> -4 $x^{2}$ + (2x + - 5x) -5

=> -4 $x^{2}$ - 3x - 5

This equation can no more be divided / simplified, so,

The answer = -4 $x^{2}$ - 3x - 5

So, in the boxes, the answer will be,

Box 1 = -4

Box 2 = -3

Box 3 = -5

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

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Simplify. 15 X plus 2Y plus X plus 7X plus 8Y

disa [49]

Answer:

23x+10y

Step-by-step explanation:

add all x variables and all y variables together

8 0

3 years ago

Jdudjdjdjkdjdkxkdjndjd

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5 0

3 years ago

1. The expression 11x2 - 12x - 10 has ___ terms and a constant of ___.

Illusion [34]

1. 3,-10

2. 10x + y

3. 2x - 3y

6 0

3 years ago

Read 2 more answers

Find the value of c that makes each trinomial a perfect square. Then write the trinomial as a perfect square.

musickatia [10]

Answer:

d. c = 100; (x – 10)²

Step-by-step explanation:

Note that (x+a)²=x²+2ax+a².

In our case, 2a=-20, so 'a' must be -10.

Since c=a², and a=-10, c=(-10²)=100.

Since a=-10, the perfect square is (x – 10)²

3 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Consider this Expression.​

Consider this Expression.