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Basile [38]
3 years ago
12

Consider this Expression.​

Mathematics
2 answers:
MrMuchimi3 years ago
6 0

Answer:

The answer is -4x^2-7x-5

Step-by-step explanation:

Alex Ar [27]3 years ago
3 0

Answer:

Box 1 = -4

Box 2 = -3

Box 3 = -5

Step-by-step explanation:

-4x^{2} + 2x - 5(1 + x)

=> -4x^{2} + 2x - 5 - 5x

=> -4x^{2} + (2x + - 5x) -5

=> -4x^{2} - 3x - 5

This equation can no more be divided / simplified, so,

The answer = -4x^{2} - 3x - 5

So, in the boxes, the answer will be,

Box 1 = -4

Box 2 = -3

Box 3 = -5

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

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-4v = -9v + 10 V=<br> Help
Aleksandr-060686 [28]

Answer:

v=2

Step-by-step explanation:

5v=10

v=2

3 0
3 years ago
Quick I need some help! Simplify to create an equivalent expression. ( photo linked)
Sophie [7]

Answer:

B. 31r − 71 is the answer!

5 0
3 years ago
Integrated mathematics 2. need help with chapter 5 test please​
Pani-rosa [81]

Answer:

1/4

Step-by-step explanation:

\text{Diamonds, spades, clubs and hearts make up the 4 suits of a deck of cards, }

\text{which contains 52 cards. There are 13 diamonds in a pack.}

\text{Probability of an event:}

\text{ Number of favorable outcomes / Total number of outcomes}

\text{Probability of getting a diamon}d = \frac{13}{52} = \frac{1}{4}.

\text{So the chance that you draw out a diamond from a deck}=\frac{1}{4} .

8 0
2 years ago
Please I don’t understand help me?!
prohojiy [21]

Answer:

BD = 35

Step-by-step explanation:

Calculate CD in right triangle ABC, then BD in right triangle BCD

Using Pythagoras' identity in both triangles.

The square on the hypotenuse is equal to the sum of the squares on the other two sides.

In Δ ADC

CD² + AD² = AC² , substitute values

CD² + 9² = 15²

CD² + 81 = 225 ( subtract 81 from both sides )

CD = 144 ( take the square root of both sides )

CD = \sqrt{144} = 12

----------------------------------------------------------------

In Δ BCD

BD² + CD² = BC² , substitute values

BD² + 12² = 37²

BD² + 144 = 1369 ( subtract 144 from both sides )

BD² = 1225 ( take the square root of both sides )

BD = \sqrt{1225} = 35

5 0
3 years ago
Read 2 more answers
Pllllllease help me asap
marishachu [46]

Answer & Step-by-step explanation:

When we see the phrase "rate of change" then it means that we are looking for the slope. So, we will need to know the formula for finding slope or the rate of change.

slope=\frac{y_2-y_1}{x_2-x_1}

Now, let's use this equation to solve for the rate of change of each question.

<u>Problem 1:</u>

Slope=\frac{2-\frac{4}{3}}{0-(-1)}\\\\Slope=\frac{\frac{2}{3}}{1}\\\\Slope=\frac{2}{3}

<em>The rate of change of this equation is 2/3</em>

<u>Problem 2:</u>

<u></u>Slope=\frac{4-2}{1-0}\\\\Slope=\frac{2}{1}\\\\Slope=2<u></u>

<em>The rate of change for this equation is 2</em>

<u>Problem 3:</u>

<u></u>Slope=\frac{10-4}{2-1}\\\\Slope=\frac{6}{1}\\\\Slope=6<u></u>

<em>The rate of change for this equation is 6</em>

4 0
3 years ago
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