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TEA [102]
3 years ago
7

Name four angles whose tangent equals 0. a. 45°, 135°, 405°, 495° c. 0°, 180°, 360°, 540° b. 90°, 270°, 450°, 630° d. 90°, 450°,

810°, 1170°

Mathematics
1 answer:
Tresset [83]3 years ago
5 0

Answer:

C. SEE ATTACHED PICTURE

Step-by-step explanation:

Tangent = 0 at 0° and 180°

0° = 360° and. 180° = 540°

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The hypotenuse of a triangle is 10 inches long. One of the legs is 6.5 inches long. what is the measurement of the missing leg?
Katarina [22]

Answer:

7.6

Step-by-step explanation:

a^2 + b^2 = c^2

6.5^2 + x^2 = 10^2

42.25 + x^2 = 100

isolate x by subtracting 42.25 on both sides

x^2 = 57.75

square root of 57.75 or 7.6

8 0
2 years ago
Chin needs more money in his net pay each month, so he plans to reduce his federal income tax deduction from 12% to 11%. His mon
matrenka [14]

Answer:

Your answer would be $2,891

Hope this help :D

Step-by-step explanation:

3 0
2 years ago
Does someone mind helping me with this question? Thank you!
Soloha48 [4]

Answer: 640

Step-by-step explanation:

The scale factor is 20/5=4, so the ratio of the areas is the square of this, or 16.

Thus, the area of ABCD is 40(16)=640.

4 0
1 year ago
Answer C? Reflexive SSS?
BARSIC [14]
Yes the answer is c. C is correct 
8 0
3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0
3 years ago
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