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Alchen [17]
3 years ago
5

Given: rectangle ABCD is similar to rectangle ZBXY.

Mathematics
2 answers:
Semmy [17]3 years ago
8 0

Answer:

The answer is D. 6

Step-by-step explanation:

Readme [11.4K]3 years ago
4 0
BX would be 6 because it is half of BC. The perimeter of ABCD is 40, dividing that by 2 would get you ZBXY's perimeter. This means divide each side by 2. 12/2=6
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2 years ago
XB−→− is the angle bisector of ∠AXC. m∠AXB=23°
Sliva [168]

Answer:

∠AXC = 46°

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Step-by-step explanation:

If XB is the angle bisector of ∠AXC then XB bisects ∠AXC t at X. Hence;

∠AXC = ∠AXB+∠BXC and ∠AXB=  ∠BXC

The equation becomes

∠AXC = ∠AXB+∠AXB

∠AXC = 2∠AXB

Given

m∠AXB=23°

Substitute the given angle into the expression above to get ∠AXC since we are not told what to find but we can as well find ∠AXC

∠AXC =2(23)

∠AXC = 46°

<em>Also note that since ∠AXB=  ∠BXC,</em> <em>then ∠BXC will be 23°</em>

3 0
3 years ago
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Andrews [41]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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maksim [4K]
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