Find the center and radius of the circle represented by the equation below.
1 answer:
Answer:
Center= (-6,-8)
Radius= 6
Step-by-step explanation:
We use the formula (x-h)^2+(y-k)^2 then plug in our numbers:
In the equation -h is 6 so our h (x-coordinate) is -6
In the equation -k is 8 so our k (y-coordinate) is -8
In the equation r^2 is 36 so we take the square root of 36 to get r which is 6.
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Answer:
y + 6 = -3(x - 1) - Point Slope
y=-x+8 - Slope Intercept
2x - 5y = 9 - Standard
Step-by-step explanation:
Point Slope Form is:
y + 6 = -3(x - 1) would be in point slope form, where the point is (1,-6) and the slope is '-3'.
Slope-intercept form is:
y=-x+8 is in slope intercept form, where '-1' is the slope and '8' is the y-intercept.
This only leaves 2x - 5y = 9, which is in standard form.