<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
1834 bfc I believe that’s the right answer
Ooo! I love these! Ok so your IQR is C or D. I might have my calculations wrong if so. Sorry!
Answer:
521418
Step-by-step explanation:
Answer:
Below in bold.
Step-by-step explanation:
c) 3 x (9^2)^3/4 x ((81^3)^5/6
= 3 x 81^3/4 x 81^15/6
= 3 x 81^(3/4 + 15/6)
= 3 x 81^13/4
= 3 x 3^13
= 3^14
= 4,782,969.
f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2
= 5^-2 x^2y^-4 / 625 x^4y^-2
= 5^-2 x^-2 y^-2 / 5^4
= 5^-6 x^-2y^-2
= 0.000064x^-2y^-2.
