Help,please It’s calculus
1 answer:
The function is a continuous function at 2 if the LHL and RHL will be the same as the limit of the function.
<h3>What is continuity of a function?</h3>It is defined as the property of a function in which the function varies continuous, and we plot the graph of a function it doesn't break.
We have a function:
If f(x) is a continuous, then it will follow:
f(2) = 2² - 2 = 4 - 2 = 2
Left-hand limit at 2 = right-hand limit at 2 = 2
Limit at 2 of a function = 2
Using limit, we can check the whether the function is differentiable or not.
Thus, the function is a continuous function at 2 if the LHL and RHL will be the same as the limit of the function.
Learn more about the continuous function here:
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9514 1404 393
Answer:
(8.49; 225°)
Step-by-step explanation:
The angle is a 3rd-quadrant angle. The reference angle will be ...
arctan(-6/-6) = 45°
In the 3rd quadrant, the angle is 45° +180° = 225°.
The magnitude of the vector to the point is its distance from the origin:
√((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49
The polar coordinates can be written as (8.49; 225°).
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<em>Additional comment</em>
My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.
