Answer:
Time taken by train in onward journey = 12 hours.
Step-by-step explanation:
Given:
Speed of train making a trip to a repair = 25 mph
Speed of train on return trip = 20 mph
Time taken for return trip = 15 hours
To find the time taken on the on wards trip.
Solution:
The distance traveled by the train on the trip and return trip is the same as the y are of same trips in opposite directions.
Distance can be calculated by using the data for the return trip.
Distance= 
Distance= 
Speed of train for on ward trip = 25 mph
Time taken = 
Time taken = 
Thus, time taken by train in onward journey = 12 hours.
Answer:
Sin 90 = 1/1 = 1
Use trigonometry formula and a triangle with lengths of 1
The second one the unit rate is 2.05 i think
The solution of the equation is x= 3 and y = 2
Step-by-step explanation:
Given,
-3x-4y = -17 and
-x-3y = -9
The system of equation can be rewritten as
3x+4y = 17 ------eq 1 and
x+3y = 9 ------ eq 2
To solve for x and y
Multiplying eq 2 by 3 we get,
3x + 9y = 27
or, 3x = 27-9y
Putting this value of x into eq 1 we get,
27-9y +4y = 17
or, -5y = 17-27
or, -5y = -10
or, y = 2
Now put y=2 in eq 2 we get,
x = 9 - 3(2)
= 3
Hence the solution is x = 3 and y = 2