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2 years ago

Please Help! Need by today!

Mathematics

2 answers:

PilotLPTM [1.2K]2 years ago

8 0

C=hsjxjfjxjkcbdhshdjsjdjdisijs

ra1l [238]2 years ago

4 0

Answer:

sorry but no one answered it sorry good lucked

Step-by-step explanation:

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The ratio of the angles of a triangle is 3:8:4. What is the size of the largest angle?

Phantasy [73]

Answer: 96°

Step-by-step explanation:

Sum of angles of a triangle = 180°

3 + 8 + 4 = 15

The biggest angle is 8/15 * 180 = 96°

7 0

3 years ago

Help, what is the answer

sp2606 [1]

The answer is d as in dog

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3 years ago

Read 2 more answers

(repost) Help Please I will Give brainliest If Correct!!

Eddi Din [679]

Answer:

There are about 7 x 10^6

Step-by-step explanation:

3.5*2029249= 7102347

rounds to 7000000= 7 x 10^6

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2 years ago

Read 2 more answers

Help please thanks quick

andrew11 [14]

Answer:

The last option has another result than the others.

Step-by-step explanation:

The first option answer is 7/2

The second option answer is 7/2

The third option answer is 7/2

The last option answer is 2/7

Hope it will help :)

6 0

3 years ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

3 years ago